Mathematics of Voting, II

The Heisman Trophy

The Heisman Trophy

A month or so ago we talked about one aspect of the mathematics of voting discussed by Dr. Orrison during his visit to OU.  In particular, we saw that in an election you can take the very same votes and get different winners depending on how you count the votes.  Of course the example given there was made up and you might think “Hey, crazy things happen when you are allowed to make things up.  I bet that never happens in real life!”

Sam Bradford is now a big fan of voting math!

Sam Bradford is a big fan of voting math!

Well, our very own Sam Bradford is the beneficiary of the mathematics of voting!  In the election to determine the winner of the Heisman Trophy the voters select candidates for first place, second place, and third place.  For first place the candidate receives 3 points, for second place 2 points, and for third place 1 point.

Here is the voting data for this year’s Heisman (taken from here):

Player School First Second Third Total points
Sam Bradford Oklahoma 300 315 196 1,726
Colt McCoy Texas 266 288 230 1,604
Tim Tebow Florida 309 207 234 1,575
Graham Harrell Texas Tech 13 44 86 213
Michael Crabtree Texas Tech 3 27 53 116
Shonn Greene Iowa 5 9 32 65
Patrick White West Virginia 3 1 8 19
Nate Davis Ball State 0 1 8 10
Rey Maualuga USC 2 1 1 9
Javon Ringer Michigan State 1 0 5 8

Notice that the Heisman voting method is exactly the same as voting method 3. in our earlier post (it isn’t hard to see that if you scale the points by multiplying by a constant or shift them by adding a constant, then it doesn’t change the order you get by totalling the points.  So multiplying by 2 and adding 1 won’t change the winner in method 3. and, hence, it’s the same as the Heisman voting method).  As we all know, by this voting method Sam Bradford was declared the winner of the Heisman Trophy this year.

Sadly, Tim Tebow doesn't know that you need more than just votes for #1

Sadly, Tim Tebow doesn't know that you need more than just votes for #1

However, let’s see what happens if you use voting method 1.  Then you only count the first place votes (so, just like in the presidential election, you really only vote for your number one candidate).  Under this scheme Tim Tebow would win the Heisman!

What about voting method 2?   Then you give each first place and second place vote 1 point, and 0 points for third place votes.  Under this scheme Sam Bradford again wins.

Sadly, Colt McCoy was confused and thought being #2 was best

Sadly, Colt McCoy was confused and thought being #2 was best

Of course, we’re mathematicians so the first thing we wonder is if there is a scheme where Colt McCoy wins.   This is a good linear algebra problem.  Say first place votes are worth 1 point, second place votes are worth s points, and third place votes are worth t points.  If you assume 1 ≥ s ≥ t ≥ 0, then are there values for s and t so that Colt McCoy wins the Hiesman?

Note that since we can rescale by multiplying by a constant, it doesn’t harm anything to assume that first place is worth 1 point.  And of course second place should be worth less than or equal to first place, and third place should be worth less than or equal to second place.  And of course Javon Ringer is SOL no matter what.

3 thoughts on “Mathematics of Voting, II

  1. Pingback: Benford’s Law and the Iranian Election « OU Math Club

  2. I’m a big fan of Tim Tebow and think he should win the Heisman this year. I know he won in 2007 but this is 2009 and he has proven his self.I want to know if I can vote

  3. Pingback: Election Day « OU Math Club

Leave a Reply

Fill in your details below or click an icon to log in:

WordPress.com Logo

You are commenting using your WordPress.com account. Log Out / Change )

Twitter picture

You are commenting using your Twitter account. Log Out / Change )

Facebook photo

You are commenting using your Facebook account. Log Out / Change )

Connecting to %s